Me 2. One of my accounts fails to recognize username/password over and over. Was able to change password but the failed log-ins continue.
I cannot log in second account. Go figure I took today off to play and relax on Everquest. You failed me again Daybreak or whatever your name is these days.
One of my accounts refuses to log in. Jesus what did they do when they moved data centres, put all the data on usb sticks or something.
They will not pay attention to your posts here. You need to "like" the first post in the "Bug" forum about this issue https://forums.daybreakgames.com/eq...edentials-at-login.263741/page-2#post-3877666
I cant log in on my main character's account. It acts like Im entering the wrong password. When I try resetting my password it doesnt seem to recognize my cell phone number for secondary authentication - the continue button remains greyed out. Petitioned on my alt character's account (this account). Please fix - raid tonight.
So I had problems yesterday with 2 of my accounts. This morning those 2 are back to working but I have a problem now with a 3rd account. It would appear that Darkpaw has implemented a Random Number Generator function in the login script. They must think it's April Fools Day or something.
Same issue with one account. Even reset password (thank you very much for that DB). Someone in CS needs to wake up and answer this please.
I am having the same problem. I cannot log my main account in at all using patchme but can using the launcher this account has a Heroic charachter on it. My second account logs in fine with launcher and patchme and this also has a Heroic character on it. My third account logs in fine with launcher and patchme and has no Heroic characters on it. Hope it gets fixed soon.
This sounds like another problem. Does your accountname contain a hypen (-) or an underscore (_)? If so, this is a different problem we already discuss here. Sorry - just noticed you are already on that thread But going to leave the comment in here in case someone else stumbles over that thread.